I'm stumped.....=(

[Ixidor]

What popular song in the 70’s basically supports the numerical fact: 0 – 0 = 0 ??
Give the song title, singer/group, and year.

hint:think of synonymns for zero'


Anyone ?

[Ptindy]

Free, with Paul Rodgers??

[Tim and Julie B]

I think it's something along the lines of "nothing minus nothing equals nothing", but I'll be darned if I can figure much else than that!:D

Julie

[Ixidor]

I don't know the song.....how does it go ?

[retic]

Money for Nothing, Dire Straits,76-80 somewhere?

[Ixidor]

Nah, don't think its dire straits either, maybe something from the jackson 5 ?

[retic]

Rock Jeopardy is my favorite, Sorry can't help ya, old 60's-80's rocker here and the Jacksons just dont cut it lol

[wetlander]

Nothing from nothing
Billy Preston ( also played key boards for Beatles on Let it Be)
1974

[retic]

Nice one, i know that one, what rock almanac did you pull that from? lol, wonder if thats it???

[Ixidor]

ahh thats it! yeah, that was a tough one

[RepTylE]

yeah I could hear some of it in my head but couldn't get it., lol

[justinO]

heres a little math stumper for you.. I *think* this was mentioned on here a long time ago.. not sure


how is 1/3 + 1/3 + 1/3 not equal to one?

1/3 = 3.3333333333333 repeated..

therefore, 1/3 + 1/3 + 1/3 == 9.9999999999 repeat.. so, without rounding.. how is this possible?

[Ptindy]

The numbers and symbols of math are a language that help us express math. Math isn't numbers and such that you learn at school, math is what we manipulate with numbers. 1/3 plus 1/3 plus 1/3 in math, is equal to 1 in math, in how it actually works. In terms of language is doesn't work but we assume we round to make the language work. Kind of like when we use the letter a as the word "a" as in "a fish", but to make it work for words that start with vowels we compenstate for simplicity with "an" and say "an apple". This is how 1/3 plus 1/3 plus 1/3 is actually equal to 1.

Mike

[noname]

Proof: 0.9999... = Sum 9/10^n
(n=1 -> Infinity)

= lim sum 9/10^n
(m -> Infinity) (n=1 -> m)

= lim .9(1-10^-(m+1))/(1-1/10)
(m -> Infinity)

= lim .9(1-10^-(m+1))/(9/10)
(m -> Infinity)

= .9/(9/10)

= 1

Found this one on the net...(As Mike so kindly informed me, my last post was off). Wow, this brings me back to the days of good ole' calculus. Anywho, it's technically possible, but who has the time to do this :)

Court